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avidsid(at)yahoo.com Guest
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Posted: Sun Apr 16, 2006 7:46 am Post subject: LED power....... |
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Yes, nice site with lots of lighting ideas...........but, no tech ideas for powering up the little buggers.....
anyone done this for their panels or other electric/electronic devices and can tell me the needed requirements to keep the LED's from burning out......?
Sid
-----------------------
Sid Hausding <avidsid(at)yahoo.com> wrote:
Wondering if all LED's come with a built in current limiting device or if most will need to have a resistor wired in line to keep the small power requirements they use from burning out.........any info posted somewhere on wiring in a 15mamp, 12dcv device to show power to the system out there?
Sid
--------------------
"Alan K. Adamson" wrote:
Opps, helps if you post the link...
http://www.ledtronics.com/
Don't know if this has been posted before or not, but this place has just
about every LED imaginable and then some.
"Why can't we all just get along?"
---------------------------------
"Why can't we all just get along?"
---------------------------------
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klehman(at)albedo.net Guest
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Posted: Sun Apr 16, 2006 8:32 am Post subject: LED power....... |
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Hi Sid
The vast majority of LED's require a current limiting resistor. A few
may have one included for example a panel indicator that specifically
says 12 volts. The operating voltage of an LED is around 1.7 volts or so
depending on the color. I usually limit the current to 8 to 15 ma. for
general use. 1000 ohms might be in the ballpark for an indicator but
play around with it. Radio shack used to have cheap paper back books
(written by Forrest Mims ?) that are great for learning things like
this. There are also a number of web sites on using LED's.
Ken
Sid Hausding wrote:
Quote: |
Yes, nice site with lots of lighting ideas...........but, no tech ideas for powering up the little buggers.....
anyone done this for their panels or other electric/electronic devices and can tell me the needed requirements to keep the LED's from burning out......?
Sid
-----------------------
Sid Hausding <avidsid(at)yahoo.com> wrote:
Wondering if all LED's come with a built in current limiting device or if most will need to have a resistor wired in line to keep the small power requirements they use from burning out.........any info posted somewhere on wiring in a 15mamp, 12dcv device to show power to the system out there?
Sid
--------------------
"Alan K. Adamson" wrote:
Opps, helps if you post the link...
http://www.ledtronics.com/
Don't know if this has been posted before or not, but this place has just
about every LED imaginable and then some.
"Why can't we all just get along?"
---------------------------------
"Why can't we all just get along?"
---------------------------------
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Mark Phillips in TN
Joined: 10 Jan 2006 Posts: 431 Location: Columbia, TN
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Posted: Sun Apr 16, 2006 8:35 am Post subject: LED power....... |
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Hi Sid-
To properly power an LED or even several in series, you simple provide an
appropriate amount of resistance in series with the correctly-biased LED(s) that
results in an actual current flow of about 20 mA. You can also reduce their
brightness by using more resistance, or less resistance, which results in
overdriving the LEDs somewhat. This will likely shorten their lifespan, but what
is 50% of maybe 100K hrs in the life of an airplane? When I first got
interested in playing with these things for my RV, I ordered a bunch of different types
and colors from Marlin P Jones, got a resistor assortment from JapShack, and
did a bunch of playing with them. The parts are extremely cheap. See:
http://mpja.com/listitems.asp?dept=116&main=122
Radio Shack carries this resistor assortment- you can make virtually any
resistance by combining resistors:
http://www.radioshack.com/product/index.jsp?productId=2062304&cp=&origkw=resis
tor&kw=resistor&kwCatId=2032058&parentPage=search
If that ugly URL doesn't work, go to Radioshack.com and search for 271-308.
If you can do Excel, I've got a SS that lists required resistances for
various types and series strings of LEDs. Will send copy direct & if anyone else
interested will send also...
Mark Phillips
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avidsid(at)yahoo.com Guest
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Posted: Sun Apr 16, 2006 9:26 am Post subject: LED power....... |
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Free cheap beer all day for Mark...........yay, and thank you profusely for getting me started. Just too lazy to review all the old manuals and relearn what I had forgotten years ago. You have provided me with the fast step to getting me back up to speed..........Happy Easter to you and yours and this list.
Sid
Avid Speedwing
----------------------------------------
Fiveonepw(at)aol.com wrote:
Hi Sid-
To properly power an LED or even several in series, you simple provide an
appropriate amount of resistance in series with the correctly-biased LED(s) that
results in an actual current flow of about 20 mA. You can also reduce their
brightness by using more resistance, or less resistance, which results in
overdriving the LEDs somewhat. This will likely shorten their lifespan, but what
is 50% of maybe 100K hrs in the life of an airplane? When I first got
interested in playing with these things for my RV, I ordered a bunch of different types
and colors from Marlin P Jones, got a resistor assortment from JapShack, and
did a bunch of playing with them. The parts are extremely cheap. See:
http://mpja.com/listitems.asp?dept=116&main=122
Radio Shack carries this resistor assortment- you can make virtually any
resistance by combining resistors:
http://www.radioshack.com/product/index.jsp?productId=2062304&cp=&origkw=resis
tor&kw=resistor&kwCatId=2032058&parentPage=search
If that ugly URL doesn't work, go to Radioshack.com and search for 271-308.
If you can do Excel, I've got a SS that lists required resistances for
various types and series strings of LEDs. Will send copy direct & if anyone else
interested will send also...
Mark Phillips
"Why can't we all just get along?"
---------------------------------
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retasker(at)optonline.net Guest
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Posted: Sun Apr 16, 2006 9:27 am Post subject: LED power....... |
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Essentially all LEDs require some sort of current limiter. That is,
LEDs are current driven devices (rather than voltage driven like a
normal incandescent lights) and putting a voltage higher than required
to light them will cause almost instant self destruction. But it looks
like you already knew that...
That said, the LED assemblies offered on the referenced site may very
well have internal limiters, especially where they come attached to a
threaded plug that is designed to thread into an incandescent lamp socket.
Most single (unassembled) LEDs do NOT have an internal limiter and are
designed to work with something between 10-30 mA through them. This can
be accomplished in a number of ways, but the simplest is just to wire a
resistor in series with the LED. When you purchase an LED it should
come with specifications that tell you what the operating voltage is
(the voltage that it lights at) and the rated maximum current. Let's
take a sample red LED with an operating voltage of 1.7V and a maximum
current of 30 mA. Let's further assume that you want to operate this at
something less than the maximum current to allow for high temperatures
in the cockpit and choose 20 mA (a little less than maximum brightness,
but probably still very bright). If we are operating this from the
alternator/battery voltage we can assume about 14V available (actually
12-14.5V - see below). If we just hooked this to the LED it would be
very bright (for a millisecond or two), then very dark . We need
to limit the current to the aforementioned 20 mA.
So... We take the available voltage (14V) and subtract what the LED
needs (1.7V) to get the voltage we need to "discard" (12.3V). We then
calculate the resistor we need to allow 20 mA with this voltage
(12.3V). Using Ohm's law (V=I*R) and rearranging (R=V/I) we plug the
numbers into the equation to get 12.3V/0.02A=615 ohms. That is not one
of the standard available values of resistor so we choose a value that
is close (620 ohms for 5% resistors or 619 ohms for 1% resistors). Now
we have a value but we still have to calculate the power "discarded" in
the resistor so we can get one that will not burn up as soon as we turn
things on. Power in watts is (W=V*I). Plugging the numbers in we get
12.3V * 0.02A = 0.246 W or 246 mW. Resistors come is various power
ratings and we have to choose one that is at least what we just
calculated. That means we should use 1/4W at absolute minimum.
However, if we choose the 1/4W resistor it will run very hot to
dissipate 0.246W of power - potentially shortening it's life and
reliability. So we really want to choose at least a 1/2W resistor.
That will give it some "elbow room" especially important if it will be
operating in a warm environment.
Use the same idea for any LED you may buy (different colors have
different operating voltages). Additionally, you can connect two LEDs
in series for whatever reason (lighting, etc.) and just do the same
calculations but use 3.4V (in this case 1.7V times the two LEDs) instead
of 1.7V. You can do this with several LEDs but you must allow some
series voltage to drop across the resistor (remembering that the voltage
on the aircraft bus varies from about 14.5V max. to about 12V min.). As
the voltage varies the LEDs will vary in brightness. If you have one
LED the "leftover" voltage will vary between 12.8V to 10.3V - a change
of approximately 20-25%. If you series several LEDs (say four for a
drop of 6.8V), the voltage will vary between 7.7V to 5.2V - a change of
30-50%. So do not add too many in series that you have too low a
voltage across the resistor.
Do not connect LEDs in parallel!!! If you do, the one that has a
slightly lower operating voltage will "hog" all the current - causing it
to use too much current (overheat) and be much brighter than the
other(s). If you want to wire them in parallel for some reason, use a
series resistor for each LED.
If you have more questions, please ask.
Dick Tasker
Sid Hausding wrote:
Quote: |
Yes, nice site with lots of lighting ideas...........but, no tech ideas for powering up the little buggers.....
anyone done this for their panels or other electric/electronic devices and can tell me the needed requirements to keep the LED's from burning out......?
Sid
-----------------------
Sid Hausding <avidsid(at)yahoo.com> wrote:
Wondering if all LED's come with a built in current limiting device or if most will need to have a resistor wired in line to keep the small power requirements they use from burning out.........any info posted somewhere on wiring in a 15mamp, 12dcv device to show power to the system out there?
Sid
--------------------
"Alan K. Adamson" wrote:
Opps, helps if you post the link...
http://www.ledtronics.com/
Don't know if this has been posted before or not, but this place has just
about every LED imaginable and then some.
"Why can't we all just get along?"
---------------------------------
"Why can't we all just get along?"
---------------------------------
|
--
Please Note:
No trees were destroyed in the sending of this message. We do concede, however,
that a significant number of electrons may have been temporarily inconvenienced.
--
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avidsid(at)yahoo.com Guest
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Posted: Sun Apr 16, 2006 9:44 am Post subject: LED power....... |
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Okay Ken,
I'm relearning some of this from a very long time ago. Its was always interesting and still is to me, just wanted a short cut to get these dang things in for indicator lights..........will search around and bring myself up to speed on some of this "old memory stuff".
Happy Holiday,
Sid
--------------------------------
Ken <klehman(at) wrote:
Hi Sid
The vast majority of LED's require a current limiting resistor. A few
may have one included for example a panel indicator that specifically
says 12 volts. The operating voltage of an LED is around 1.7 volts or so
depending on the color. I usually limit the current to 8 to 15 ma. for
general use. 1000 ohms might be in the ballpark for an indicator but
play around with it. Radio shack used to have cheap paper back books
(written by Forrest Mims ?) that are great for learning things like
this. There are also a number of web sites on using LED's.
Ken
Sid Hausding wrote:
Quote: |
Yes, nice site with lots of lighting ideas...........but, no tech ideas for powering up the little buggers.....
anyone done this for their panels or other electric/electronic devices and can tell me the needed requirements to keep the LED's from burning out......?
Sid
-----------------------
Sid Hausding wrote:
Wondering if all LED's come with a built in current limiting device or if most will need to have a resistor wired in line to keep the small power requirements they use from burning out.........any info posted somewhere on wiring in a 15mamp, 12dcv device to show power to the system out there?
Sid
--------------------
"Alan K. Adamson" wrote:
Opps, helps if you post the link...
http://www.ledtronics.com/
Don't know if this has been posted before or not, but this place has just
about every LED imaginable and then some.
"Why can't we all just get along?"
---------------------------------
"Why can't we all just get along?"
---------------------------------
|
"Why can't we all just get along?"
---------------------------------
| - The Matronics AeroElectric-List Email Forum - | | Use the List Feature Navigator to browse the many List utilities available such as the Email Subscriptions page, Archive Search & Download, 7-Day Browse, Chat, FAQ, Photoshare, and much more:
http://www.matronics.com/Navigator?AeroElectric-List |
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rhdudley(at)att.net Guest
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Posted: Sun Apr 16, 2006 9:44 am Post subject: LED power....... |
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Hi Sid,
Bob Nucolls has piece on LEDs. I think that it answers many of your
questions.
Try this link: http://www.aeroelectric.com/articles/leds3.pdf
Regards,
Richard Dudley
-6A flying
Sid Hausding wrote:
Quote: |
Yes, nice site with lots of lighting ideas...........but, no tech ideas for powering up the little buggers.....
anyone done this for their panels or other electric/electronic devices and can tell me the needed requirements to keep the LED's from burning out......?
Sid
-----------------------
Sid Hausding <avidsid(at)yahoo.com> wrote:
Wondering if all LED's come with a built in current limiting device or if most will need to have a resistor wired in line to keep the small power requirements they use from burning out.........any info posted somewhere on wiring in a 15mamp, 12dcv device to show power to the system out there?
Sid
--------------------
"Alan K. Adamson" wrote:
Opps, helps if you post the link...
http://www.ledtronics.com/
Don't know if this has been posted before or not, but this place has just
about every LED imaginable and then some.
"Why can't we all just get along?"
---------------------------------
"Why can't we all just get along?"
---------------------------------
|
| - The Matronics AeroElectric-List Email Forum - | | Use the List Feature Navigator to browse the many List utilities available such as the Email Subscriptions page, Archive Search & Download, 7-Day Browse, Chat, FAQ, Photoshare, and much more:
http://www.matronics.com/Navigator?AeroElectric-List |
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avidsid(at)yahoo.com Guest
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Posted: Sun Apr 16, 2006 10:00 am Post subject: LED power....... |
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you're going to be a great instructor in you "other" life.........and thanks a million, now I don't even have to read anymore..........just follow your little examples and "getter' done" as the cable guy says.............and a Happy Holiday to you and the family also. Great info this morning........
Sid
I even used to know Ohm's law..........
------------------
"Richard E. Tasker" <retasker(at)> wrote:
Essentially all LEDs require some sort of current limiter. That is,
LEDs are current driven devices (rather than voltage driven like a
normal incandescent lights) and putting a voltage higher than required
to light them will cause almost instant self destruction. But it looks
like you already knew that...
That said, the LED assemblies offered on the referenced site may very
well have internal limiters, especially where they come attached to a
threaded plug that is designed to thread into an incandescent lamp socket.
Most single (unassembled) LEDs do NOT have an internal limiter and are
designed to work with something between 10-30 mA through them. This can
be accomplished in a number of ways, but the simplest is just to wire a
resistor in series with the LED. When you purchase an LED it should
come with specifications that tell you what the operating voltage is
(the voltage that it lights at) and the rated maximum current. Let's
take a sample red LED with an operating voltage of 1.7V and a maximum
current of 30 mA. Let's further assume that you want to operate this at
something less than the maximum current to allow for high temperatures
in the cockpit and choose 20 mA (a little less than maximum brightness,
but probably still very bright). If we are operating this from the
alternator/battery voltage we can assume about 14V available (actually
12-14.5V - see below). If we just hooked this to the LED it would be
very bright (for a millisecond or two), then very dark . We need
to limit the current to the aforementioned 20 mA.
So... We take the available voltage (14V) and subtract what the LED
needs (1.7V) to get the voltage we need to "discard" (12.3V). We then
calculate the resistor we need to allow 20 mA with this voltage
(12.3V). Using Ohm's law (V=I*R) and rearranging (R=V/I) we plug the
numbers into the equation to get 12.3V/0.02A=615 ohms. That is not one
of the standard available values of resistor so we choose a value that
is close (620 ohms for 5% resistors or 619 ohms for 1% resistors). Now
we have a value but we still have to calculate the power "discarded" in
the resistor so we can get one that will not burn up as soon as we turn
things on. Power in watts is (W=V*I). Plugging the numbers in we get
12.3V * 0.02A = 0.246 W or 246 mW. Resistors come is various power
ratings and we have to choose one that is at least what we just
calculated. That means we should use 1/4W at absolute minimum.
However, if we choose the 1/4W resistor it will run very hot to
dissipate 0.246W of power - potentially shortening it's life and
reliability. So we really want to choose at least a 1/2W resistor.
That will give it some "elbow room" especially important if it will be
operating in a warm environment.
Use the same idea for any LED you may buy (different colors have
different operating voltages). Additionally, you can connect two LEDs
in series for whatever reason (lighting, etc.) and just do the same
calculations but use 3.4V (in this case 1.7V times the two LEDs) instead
of 1.7V. You can do this with several LEDs but you must allow some
series voltage to drop across the resistor (remembering that the voltage
on the aircraft bus varies from about 14.5V max. to about 12V min.). As
the voltage varies the LEDs will vary in brightness. If you have one
LED the "leftover" voltage will vary between 12.8V to 10.3V - a change
of approximately 20-25%. If you series several LEDs (say four for a
drop of 6.8V), the voltage will vary between 7.7V to 5.2V - a change of
30-50%. So do not add too many in series that you have too low a
voltage across the resistor.
Do not connect LEDs in parallel!!! If you do, the one that has a
slightly lower operating voltage will "hog" all the current - causing it
to use too much current (overheat) and be much brighter than the
other(s). If you want to wire them in parallel for some reason, use a
series resistor for each LED.
If you have more questions, please ask.
Dick Tasker
Sid Hausding wrote:
Quote: |
Yes, nice site with lots of lighting ideas...........but, no tech ideas for powering up the little buggers.....
anyone done this for their panels or other electric/electronic devices and can tell me the needed requirements to keep the LED's from burning out......?
Sid
-----------------------
Sid Hausding wrote:
Wondering if all LED's come with a built in current limiting device or if most will need to have a resistor wired in line to keep the small power requirements they use from burning out.........any info posted somewhere on wiring in a 15mamp, 12dcv device to show power to the system out there?
Sid
--------------------
"Alan K. Adamson" wrote:
Opps, helps if you post the link...
http://www.ledtronics.com/
Don't know if this has been posted before or not, but this place has just
about every LED imaginable and then some.
"Why can't we all just get along?"
---------------------------------
"Why can't we all just get along?"
---------------------------------
|
--
Please Note:
No trees were destroyed in the sending of this message. We do concede, however,
that a significant number of electrons may have been temporarily inconvenienced.
--
"Why can't we all just get along?"
---------------------------------
| - The Matronics AeroElectric-List Email Forum - | | Use the List Feature Navigator to browse the many List utilities available such as the Email Subscriptions page, Archive Search & Download, 7-Day Browse, Chat, FAQ, Photoshare, and much more:
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jschroeder(at)perigee.net Guest
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Posted: Sun Apr 16, 2006 11:42 am Post subject: LED power....... |
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Sid -
Most LEDs you get do not have the resistors needed to bias them. Sooo, you
need to do this. Most fixtures using LED's these days come with the
biasing already installed for that particular fixture/light. All of the
replacement bulbs for cars have the bias installed.
Try the following for some of the how-to stuff:
http://www.eaa724.org/TechnicalStuff%20.html
http://ourworld.compuserve.com/homepages/Bill_Bowden/led.htm
http://members.misty.com/don/ledx.html
http://metku.net/index.html?sect=view&n=1&path=mods/ledcalc/index_eng
This should get you going.
John Schroeder
On Sun, 16 Apr 2006 08:44:40 -0700 (PDT), Sid Hausding <avidsid(at)yahoo.com>
wrote:
Quote: |
Yes, nice site with lots of lighting ideas...........but, no tech ideas
for powering up the little buggers.....
anyone done this for their panels or other electric/electronic devices
and can tell me the needed requirements to keep the LED's from burning
out......?
Sid
|
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Peter Laurence
Joined: 10 Jan 2006 Posts: 50
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Posted: Mon Apr 17, 2006 6:32 am Post subject: LED power....... |
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|
Dick
Nice explanation.
Would you give us a scenarion using a voltage regulator in a current
limiting mode?
Peter Laurence
Quote: | Essentially all LEDs require some sort of current limiter. That is,
LEDs are current driven devices (rather than voltage driven like a
normal incandescent lights) and putting a voltage higher than required
to light them will cause almost instant self destruction. But it looks
like you already knew that...
That said, the LED assemblies offered on the referenced site may very
well have internal limiters, especially where they come attached to a
threaded plug that is designed to thread into an incandescent lamp socket.
Most single (unassembled) LEDs do NOT have an internal limiter and are
designed to work with something between 10-30 mA through them. This can
be accomplished in a number of ways, but the simplest is just to wire a
resistor in series with the LED. When you purchase an LED it should
come with specifications that tell you what the operating voltage is
(the voltage that it lights at) and the rated maximum current. Let's
take a sample red LED with an operating voltage of 1.7V and a maximum
current of 30 mA. Let's further assume that you want to operate this at
something less than the maximum current to allow for high temperatures
in the cockpit and choose 20 mA (a little less than maximum brightness,
but probably still very bright). If we are operating this from the
alternator/battery voltage we can assume about 14V available (actually
12-14.5V - see below). If we just hooked this to the LED it would be
very bright (for a millisecond or two), then very dark . We need
to limit the current to the aforementioned 20 mA.
So... We take the available voltage (14V) and subtract what the LED
needs (1.7V) to get the voltage we need to "discard" (12.3V). We then
calculate the resistor we need to allow 20 mA with this voltage
(12.3V). Using Ohm's law (V=I*R) and rearranging (R=V/I) we plug the
numbers into the equation to get 12.3V/0.02A=615 ohms. That is not one
of the standard available values of resistor so we choose a value that
is close (620 ohms for 5% resistors or 619 ohms for 1% resistors). Now
we have a value but we still have to calculate the power "discarded" in
the resistor so we can get one that will not burn up as soon as we turn
things on. Power in watts is (W=V*I). Plugging the numbers in we get
12.3V * 0.02A = 0.246 W or 246 mW. Resistors come is various power
ratings and we have to choose one that is at least what we just
calculated. That means we should use 1/4W at absolute minimum.
However, if we choose the 1/4W resistor it will run very hot to
dissipate 0.246W of power - potentially shortening it's life and
reliability. So we really want to choose at least a 1/2W resistor.
That will give it some "elbow room" especially important if it will be
operating in a warm environment.
Use the same idea for any LED you may buy (different colors have
different operating voltages). Additionally, you can connect two LEDs
in series for whatever reason (lighting, etc.) and just do the same
calculations but use 3.4V (in this case 1.7V times the two LEDs) instead
of 1.7V. You can do this with several LEDs but you must allow some
series voltage to drop across the resistor (remembering that the voltage
on the aircraft bus varies from about 14.5V max. to about 12V min.). As
the voltage varies the LEDs will vary in brightness. If you have one
LED the "leftover" voltage will vary between 12.8V to 10.3V - a change
of approximately 20-25%. If you series several LEDs (say four for a
drop of 6.8V), the voltage will vary between 7.7V to 5.2V - a change of
30-50%. So do not add too many in series that you have too low a
voltage across the resistor.
Do not connect LEDs in parallel!!! If you do, the one that has a
slightly lower operating voltage will "hog" all the current - causing it
to use too much current (overheat) and be much brighter than the
other(s). If you want to wire them in parallel for some reason, use a
series resistor for each LED.
If you have more questions, please ask.
Dick Tasker
Sid Hausding wrote:
>
>
>Yes, nice site with lots of lighting ideas...........but, no tech ideas
>for powering up the little buggers.....
> anyone done this for their panels or other electric/electronic devices
> and can tell me the needed requirements to keep the LED's from burning
> out......?
> Sid
> -----------------------
>
>Sid Hausding <avidsid(at)yahoo.com> wrote:
>
>
>Wondering if all LED's come with a built in current limiting device or if
>most will need to have a resistor wired in line to keep the small power
>requirements they use from burning out.........any info posted somewhere
>on wiring in a 15mamp, 12dcv device to show power to the system out there?
>Sid
>--------------------
>
>"Alan K. Adamson" wrote:
>
>
>Opps, helps if you post the link...
>
>http://www.ledtronics.com/
>
>Don't know if this has been posted before or not, but this place has just
>about every LED imaginable and then some.
>
>"Why can't we all just get along?"
>
>---------------------------------
>
>"Why can't we all just get along?"
>
>---------------------------------
>
--
Please Note:
No trees were destroyed in the sending of this message. We do concede,
however,
that a significant number of electrons may have been temporarily
inconvenienced.
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retasker(at)optonline.net Guest
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Posted: Mon Apr 17, 2006 1:13 pm Post subject: LED power....... |
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In concept it is really simple .
The quickest way (since you can probably get the parts at Radshack) is
to use a three terminal regulator (in, out, ground) like the LM7805
series, although any voltage regulator will work. Connect a resistor
between the output of the regulator and the ground pin of the regulator
(do NOT connect the regulator ground pin to aircraft ground). Connect
the LED and the regulator assembly in series between +14V and ground -
it doesn't matter if you have the regulator connected to +14V to the LED
and then to ground or vice versa. For example, connect the input of the
regulator to +14V, the ground pin of the regulator/resistor to the
positive terminal of the LED and the negative terminal of the LED to
aircraft ground. You also must add appropriate capacitors per the
manufacturers datasheet recommendation - I really can't make any
recommendations here as each regulator is different.
Choose the resistor value based on how much current you want as
follows: Let's assume you want 20 mA and you have chosen a 5V
regulator. Calculate the resistor value (using ohms law) R = 5V / 0.2
mA = 250 ohms. The power dissipated in the resistor is P = 5V * 0.02mA
= 0.1W. In this case a 1/4 W resistor is fine.
Depending on how much current you choose and how many LEDs you use you
may have to add a heat sink to the regulator (unlikely). Bur just in
case, you calculate the power dissipated in the regulator like so
(assuming use of a 5V regulator): Find the maximum voltage across the
regulator +14.5V- 5V - 1.7V = 7.8V. Multiply that by the current, which
is essentially whatever you chose earlier (20 mA in this case) 7.8V *
0.02mA = 0.156W - a number that all but the smallest regulators can
handle without a heatsink.
As with a resistor limiter, you can use more than one LED in series.
You have to have enough voltage when you add all the voltage drops to
still be lower than the minimum expected aircraft supply voltage
(typically about 12V). The voltages that you must add together are: the
5V due to the regulator, the LED drop * the number of LEDs and the
minimum voltage required across the regulator itself (not the 5V, but a
voltage called the dropout voltage which is anywhere from several volts
to less than a volt - depending on the actual regulator used). As an
example, using a LM7805 with 2V dropout, you would have 12V - 5V - 2V =
5V, meaning you could drive three red LEDs down to about the 12V. You
can also find regulators that allow a smaller output voltage (than 5V)
which means that you have more for the LEDs - for instance, the LP2950
is available in a 3V version and this also has a lower dropout voltage
of about 0.5V.
The advantage of using an active regulator is that the current (and
therefore brightness) is essentially constant over the full aircraft
supply voltage (12V to 14.5V). The disadvantage is that it is a little
more complicated than a simple series resistor.
Dick Tasker
Peter Laurence wrote:
Quote: |
Dick
Nice explanation.
Would you give us a scenarion using a voltage regulator in a current
limiting mode?
Peter Laurence
>Essentially all LEDs require some sort of current limiter. That is,
>LEDs are current driven devices (rather than voltage driven like a
>normal incandescent lights) and putting a voltage higher than required
>to light them will cause almost instant self destruction. But it looks
>like you already knew that...
>
>That said, the LED assemblies offered on the referenced site may very
>well have internal limiters, especially where they come attached to a
>threaded plug that is designed to thread into an incandescent lamp socket.
>
>Most single (unassembled) LEDs do NOT have an internal limiter and are
>designed to work with something between 10-30 mA through them. This can
>be accomplished in a number of ways, but the simplest is just to wire a
>resistor in series with the LED. When you purchase an LED it should
>come with specifications that tell you what the operating voltage is
>(the voltage that it lights at) and the rated maximum current. Let's
>take a sample red LED with an operating voltage of 1.7V and a maximum
>current of 30 mA. Let's further assume that you want to operate this at
>something less than the maximum current to allow for high temperatures
>in the cockpit and choose 20 mA (a little less than maximum brightness,
>but probably still very bright). If we are operating this from the
>alternator/battery voltage we can assume about 14V available (actually
>12-14.5V - see below). If we just hooked this to the LED it would be
>very bright (for a millisecond or two), then very dark . We need
>to limit the current to the aforementioned 20 mA.
>
>So... We take the available voltage (14V) and subtract what the LED
>needs (1.7V) to get the voltage we need to "discard" (12.3V). We then
>calculate the resistor we need to allow 20 mA with this voltage
>(12.3V). Using Ohm's law (V=I*R) and rearranging (R=V/I) we plug the
>numbers into the equation to get 12.3V/0.02A=615 ohms. That is not one
>of the standard available values of resistor so we choose a value that
>is close (620 ohms for 5% resistors or 619 ohms for 1% resistors). Now
>we have a value but we still have to calculate the power "discarded" in
>the resistor so we can get one that will not burn up as soon as we turn
>things on. Power in watts is (W=V*I). Plugging the numbers in we get
>12.3V * 0.02A = 0.246 W or 246 mW. Resistors come is various power
>ratings and we have to choose one that is at least what we just
>calculated. That means we should use 1/4W at absolute minimum.
>However, if we choose the 1/4W resistor it will run very hot to
>dissipate 0.246W of power - potentially shortening it's life and
>reliability. So we really want to choose at least a 1/2W resistor.
>That will give it some "elbow room" especially important if it will be
>operating in a warm environment.
>
>Use the same idea for any LED you may buy (different colors have
>different operating voltages). Additionally, you can connect two LEDs
>in series for whatever reason (lighting, etc.) and just do the same
>calculations but use 3.4V (in this case 1.7V times the two LEDs) instead
>of 1.7V. You can do this with several LEDs but you must allow some
>series voltage to drop across the resistor (remembering that the voltage
>on the aircraft bus varies from about 14.5V max. to about 12V min.). As
>the voltage varies the LEDs will vary in brightness. If you have one
>LED the "leftover" voltage will vary between 12.8V to 10.3V - a change
>of approximately 20-25%. If you series several LEDs (say four for a
>drop of 6.8V), the voltage will vary between 7.7V to 5.2V - a change of
>30-50%. So do not add too many in series that you have too low a
>voltage across the resistor.
>
>Do not connect LEDs in parallel!!! If you do, the one that has a
>slightly lower operating voltage will "hog" all the current - causing it
>to use too much current (overheat) and be much brighter than the
>other(s). If you want to wire them in parallel for some reason, use a
>series resistor for each LED.
>
>If you have more questions, please ask.
>
>Dick Tasker
>
>Sid Hausding wrote:
>
>
>
>>
>>
>>Yes, nice site with lots of lighting ideas...........but, no tech ideas
>>for powering up the little buggers.....
>> anyone done this for their panels or other electric/electronic devices
>>and can tell me the needed requirements to keep the LED's from burning
>>out......?
>> Sid
>> -----------------------
>>
>>Sid Hausding <avidsid(at)yahoo.com> wrote:
>>
>>
>>Wondering if all LED's come with a built in current limiting device or if
>>most will need to have a resistor wired in line to keep the small power
>>requirements they use from burning out.........any info posted somewhere
>>on wiring in a 15mamp, 12dcv device to show power to the system out there?
>>Sid
>>--------------------
>>
>>"Alan K. Adamson" wrote:
>>
>>
>>Opps, helps if you post the link...
>>
>>http://www.ledtronics.com/
>>
>>
>>
>>Don't know if this has been posted before or not, but this place has just
>>about every LED imaginable and then some.
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>"Why can't we all just get along?"
>>
>>---------------------------------
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>"Why can't we all just get along?"
>>
>>---------------------------------
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>--
>Please Note:
>No trees were destroyed in the sending of this message. We do concede,
>however,
>that a significant number of electrons may have been temporarily
>inconvenienced.
>--
>
>
>
>
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william.p.dube(at)noaa.go Guest
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Posted: Mon Apr 17, 2006 3:41 pm Post subject: LED power....... |
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If you are going to go through the effort to use a regulator, use an
LM317 instead. You can easily set it up as a current regulator and it
will put exactly 20 mA (or whatever you choose) through the LED.
Attached is a wiring diagram.
Here is a nice web page that gives all the basic "how to" for
running LEDs.
http://www.trainweb.org/girr/tips/tips7/white_led_tips.html
Use a 60 ohm resistor with the lm317 to get exactly 20 mA. A 62 ohm
will give slightly less, but you will never notice and it is a standard
value.
Here is the digikey order page for the style you would want to get.
Notice that thy cost less than $0.50.
http://www.digikey.com/scripts/DkSearch/dksus.dll?Detail?Ref=357151&Row=74749&Site=US
Get the TO-92 package as you don't need the large current that the
larger package will supply. You also don't want surface mount.
Bill Dube'
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