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dvanlanen
Joined: 25 Jul 2006 Posts: 122 Location: Madison, WI
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Posted: Wed Jun 18, 2008 11:35 am Post subject: Contactor Diodes |
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I am reading Chapter 11 of the AeroElectric manual, pp. 11-20 and 11-21 regarding battery and starter contactors, and I am having trouble understanding the use of diodes for spike protection.
In figure 11-20 for a battery contactor, the diode is connected between the coil terminal and the large battery terminal. When the contactor switch is opened, and the magnetic field of the coil collapses, what prevents an electrical spike from traveling directly out of the coil back through the 22AWG wire to the master switch, bypassing the diode, which is shown as being wired “in parallel” to the coil?
In figure 11-21 for a starter contactor, the direction of the diode appears to prevent a flow to ground, where there are no electrical components to protect. Again, what would prevent the spike from traveling back through the 20AWG wire to the starter switch, bypassing the diode?
I’m sure these are “dumb” questions, but I’m not very quick at picking up some of these things as some folks are. I would appreciate help in understanding it.
Thanks,
Dave Van Lanen
Do Not Archive [quote][b]
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bob(at)bob-white.com Guest
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Posted: Wed Jun 18, 2008 12:02 pm Post subject: Contactor Diodes |
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On Wed, 18 Jun 2008 14:29:23 -0500
"Dave VanLanen" <davevanlanen(at)sbcglobal.net> wrote:
Quote: | I am reading Chapter 11 of the AeroElectric manual, pp. 11-20 and 11-21
regarding battery and starter contactors, and I am having trouble
understanding the use of diodes for spike protection.
In figure 11-20 for a battery contactor, the diode is connected between the
coil terminal and the large battery terminal. When the contactor switch is
opened, and the magnetic field of the coil collapses, what prevents an
electrical spike from traveling directly out of the coil back through the
22AWG wire to the master switch, bypassing the diode, which is shown as
being wired "in parallel" to the coil?
In figure 11-21 for a starter contactor, the direction of the diode appears
to prevent a flow to ground, where there are no electrical components to
protect. Again, what would prevent the spike from traveling back through
the 20AWG wire to the starter switch, bypassing the diode?
I'm sure these are "dumb" questions, but I'm not very quick at picking up
some of these things as some folks are. I would appreciate help in
understanding it.
Thanks,
Dave Van Lanen
Do Not Archive
Hi Dave,
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When you interrupt the current flow through a coil, there is a voltage
produced that is proportional to the speed that the current changes. It
is also the opposite polarity to the voltage that was applied to
generate the current flow in the first place. What the diode does is
provide a low impedance load for the reverse polarity spike. Voltage
will be limited to the forward voltage of the diode, and current flow
will decay more slowly. That's why the coil drop out time is increased
when the spike protection is used.
Bob W.
--
N93BD - Rotary Powered BD-4 - http://www.bob-white.com
3.8 Hours Total Time and holding
Cables for your rotary installation - http://roblinstores.com/cables/
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nuckolls.bob(at)cox.net Guest
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Posted: Wed Jun 18, 2008 3:37 pm Post subject: Contactor Diodes |
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At 02:29 PM 6/18/2008 -0500, you wrote:
Quote: | I am reading Chapter 11 of the AeroElectric manual, pp. 11-20 and 11-21
regarding battery and starter contactors, and I am having trouble
understanding the use of diodes for spike protection.
In figure 11-20 for a battery contactor, the diode is connected between
the coil terminal and the large battery terminal. When the contactor
switch is opened, and the magnetic field of the coil collapses, what
prevents an electrical spike from traveling directly out of the coil back
through the 22AWG wire to the master switch, bypassing the diode, which is
shown as being wired in parallel to the coil?
In figure 11-21 for a starter contactor, the direction of the diode
appears to prevent a flow to ground, where there are no electrical
components to protect. Again, what would prevent the spike from traveling
back through the 20AWG wire to the starter switch, bypassing the diode?
I m sure these are dumb questions, but I m not very quick at picking up
some of these things as some folks are. I would appreciate help in
understanding it.
|
No problem Dave,
See:
http://www.aeroelectric.com/articles/spike.pdf
http://www.aeroelectric.com/articles/spikecatcher.pdf
If these don't answer or satisfactorily explain
then get back with us here on the List.
Bob . . .
----------------------------------------)
( . . . a long habit of not thinking )
( a thing wrong, gives it a superficial )
( appearance of being right . . . )
( )
( -Thomas Paine 1776- )
----------------------------------------
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dvanlanen
Joined: 25 Jul 2006 Posts: 122 Location: Madison, WI
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Posted: Thu Jun 19, 2008 3:04 pm Post subject: Contactor Diodes |
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I am still confused, but I think my reading of the second document might help me clarify my questions. This document states that the spike is negative-going, which I assume means that it is flowing toward ground (?) If this is true, then it leads me to two related questions: 1) If the spike is travelling toward ground, why would it hurt the switch, which is installed in the positive wire?, and 2) Why would the spike be stopped by the diode when it could more easily travel through the coil wire directly to ground? This last question may be a lack of understanding of how a diode works - does it “block” the spike from travelling against the arrowhead in the diagram, or does it actually “absorb” the spike?
Thanks,
Dave
Date: Jun 18, 2008
From: "Robert L. Nuckolls, III" <nuckolls.bob(at)cox.net>
Subject: Re: Contactor Diodes
I am reading Chapter 11 of the AeroElectric manual, pp. 11-20 and 11-21
>regarding battery and starter contactors, and I am having trouble
>understanding the use of diodes for spike protection.
>
>In figure 11-20 for a battery contactor, the diode is connected between
>the coil terminal and the large battery terminal. When the contactor
>switch is opened, and the magnetic field of the coil collapses, what
>prevents an electrical spike from traveling directly out of the coil back
>through the 22AWG wire to the master switch, bypassing the diode, which is
>shown as being wired in parallel to the coil?
>
>In figure 11-21 for a starter contactor, the direction of the diode
>appears to prevent a flow to ground, where there are no electrical
>components to protect. Again, what would prevent the spike from traveling
>back through the 20AWG wire to the starter switch, bypassing the diode?
>
>I m sure these are dumb questions, but I m not very quick at picking up
>some of these things as some folks are. I would appreciate help in
>understanding it.
No problem Dave,
See:
http://www.aeroelectric.com/articles/spike.pdf
http://www.aeroelectric.com/articles/spikecatcher.pdf
If these don't answer or satisfactorily explain
then get back with us here on the List.
Bob . . . [quote][b]
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nuckolls.bob(at)cox.net Guest
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Posted: Thu Jun 19, 2008 5:42 pm Post subject: Contactor Diodes |
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At 05:58 PM 6/19/2008 -0500, you wrote:
Quote: | I am still confused, but I think my reading of the second document might
help me clarify my questions. This document states that the spike is
negative-going, which I assume means that it is flowing toward ground
(?) If this is true, then it leads me to two related questions: 1) If
the spike is travelling toward ground, why would it hurt the switch, which
is installed in the positive wire?
|
Polarity isn't the risk . . . it's VOLTAGE. The dielectric
strength of air (insulation quality) is on the order of 700
volts per mil. Okay, how far apart are the contacts of a switch
when they first open. Microinches? Nanoinches? Naw . . . damned
SMALL inches. How many volts does it take to jump across
damned small inches? damned small volts.
So, this says that any time you break the contacts of any circuit
there is a tiny little fire that strikes up in the gap. Now,
depending on the energy stored (no much but enough to certainly
feel if you put your finger on it), how fast the rate of rise
for votlage (pretty quick, see graphs), spreading velocity of
contacts (the faster they open the more likely they are to break
the arc) and their mass (the heavier, the more heat they take
out of the arc and promote quenching), there is some erosion
of contact surface.
We largely ignored it during the first 4 decades of aviation
mostly out of lack of technical imperative combined with
some ignorance. The cost of replacing a switch from time to
time was quite small in the overall cost of owning an airplane.
But about 10-12 years ago, the first of the two-stage
starter solenoids started showing up on both OBAM and
TC aircraft. The energy stored on the coils for these
devices took a big jump and we saw a rash of contact
failures in the legacy OFF-L-R-BOTH-START style keyswitches.
This prompted the AD against ACS and similar switches
for replacement of starter solenoid control contacts
in the switch and ADDING the spike catcher diode. Problem
was, as described in the article, the diode was originally
installed across the switch in a manner that did not
perform as needed. It was ultimately corrected and
re-published to put the diode across the contactor coil.
Quote: | , and 2) Why would the spike be stopped by the diode when it could more easily
travel through the coil wire directly to ground?
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Don't understand this . . . since the induced voltage
caused by coil collapse is negative going at switch
when the switch opens, and the diode (a check valve for
electron flow) is positioned to conduct for any voltage
that attempts to go more negative than ground, the
spike current presented at the switch end is indeed
shunted to ground and returns to the coil through
ground. Virtually ALL the energy stored in the coil's
magnetic field is dissipated in THE RESISTANCE OF
THE COIL over tens of milliseconds.
Review the write up on Kettering ignition system
in chapter on OV relays. Kettering's points/coil/
distributor exploited this effect to generate a
multi-kilovolt spike from a 6v car battery. Here
he WANTED the spike to live long and prosper. In
our case, the same kind of spike has deleterious
effects on the contacts of the controlling switch.
Kettering used 'condenser' to mitigate deleterious
effects on points.
Quote: | This last question may be a lack of understanding of how a diode works
- does it block the spike from travelling against the arrowhead in the
diagram, or does it actually absorb the spike?
|
It's a check valve for electrons. Electrons flow
through the device only in direction opposite the
arrowhead. See description in Chapter 1.
Oh yeah, sorry about that first article. Noticed
later it didn't have the information I was thinking
about. I'm not sure where the right one got off too.
I've been reorganizing the website indexes. I'll find
it evenually.
Bob . . .
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dvanlanen
Joined: 25 Jul 2006 Posts: 122 Location: Madison, WI
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Posted: Sun Jun 22, 2008 5:22 pm Post subject: Contactor Diodes |
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Bob,
I think I mis-stated question 2. What I meant to say was, “why would the spike be stopped by the diode when it could more easily travel through the coil wire directly to the opening switch?”
In reading your reply carefully, I believe I might be misunderstanding the actual “flow” of energy in this instance. When you say that the diode is positioned to conduct for any voltage that attempts to go more negative than ground, are you saying that the spike will be conducted through the diode (in the direction of the arrow) and back to the coil, and that this cycle will continue until the resistance of the coil dissipates it? If so, what makes the diode a “preferred” path over the path through the wire to the opening switch? Is this just the nature of a diode?
I apologize if I am taking up too much of this venue’s resouces in trying to understand this concept. If this is an issue, please let me know and I will try to gain an understanding by finding someone locally to discuss in more detail.
Thanks,
Dave
and 2) Why would the spike be stopped by the diode when it could more easily
> travel through the coil wire directly to ground?
Don't understand this . . . since the induced voltage
caused by coil collapse is negative going at switch
when the switch opens, and the diode (a check valve for
electron flow) is positioned to conduct for any voltage
that attempts to go more negative than ground, the
spike current presented at the switch end is indeed
shunted to ground and returns to the coil through
ground. Virtually ALL the energy stored in the coil's
magnetic field is dissipated in THE RESISTANCE OF
THE COIL over tens of milliseconds.
Review the write up on Kettering ignition system
in chapter on OV relays. Kettering's points/coil/
distributor exploited this effect to generate a
multi-kilovolt spike from a 6v car battery. Here
he WANTED the spike to live long and prosper. In
our case, the same kind of spike has deleterious
effects on the contacts of the controlling switch.
Kettering used 'condenser' to mitigate deleterious
effects on points. [quote][b]
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nuckolls.bob(at)cox.net Guest
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Posted: Mon Jun 23, 2008 6:02 am Post subject: Contactor Diodes |
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At 08:18 PM 6/22/2008 -0500, you wrote:
Quote: | Bob,
I think I mis-stated question 2. What I meant to say was, why would the
spike be stopped by the diode when it could more easily travel through the
coil wire directly to the opening switch?
In reading your reply carefully, I believe I might be misunderstanding the
actual flow of energy in this instance. When you say that the diode is
positioned to conduct for any voltage that attempts to go more negative
than ground, are you saying that the spike will be conducted through the
diode (in the direction of the arrow) and back to the coil, and that this
cycle will continue until the resistance of the coil dissipates it? If
so, what makes the diode a preferred path over the path through the wire
to the opening switch? Is this just the nature of a diode?
|
Reactive devices (capacitors and inductors) store energy.
Capacitors in terms of the voltage to which they are charged
and the value of their capacitance. The quantity of energy
stored is
J(watt-seconds)=(CE^2)/2
Inductors do the same thing with current where energy
stored is
J=(LI^2)/2
Capacitors can give up their energy in the form of
high current pulses (like shorting a charged capacitor)
while inductors are able to produce high voltages (when
their magnetic fields are allowed to collapse without
restraint).
In the case of energy stored on an inductor like a
starter or battery contactor coil, the breaking of the energizing
circuit allows rapid collapse of the magnetic field within
the inductor . . . and if totally unrestrained, can generate
short spikes of voltage 300 volts or more.
Obviously, this voltage will easily jump the gap in the
relatively slow spreading contacts of the controlling
switch. So as demonstrated on the bench and subsequent
scope traces, a tiny fire is kindled between the spreading
contacts and most of the store energy is dissipated in
the stoking of that fire . . . with consequences to the
surface of the contacts that reduce switch life.
The goal is to re-route that energy. There's a host of
methodologies, all perform as advertised and as dictated
by the physics of their respective capabilities. A simple
diode around the coil provides a shunt path for that
energy that not only prevents the voltage from building
at all, but causes it to dissipate almost totally within
the resistance of the subject contactor coil. See:
http://www.aeroelectric.com/Pictures/Curves/S704-1_Drop-Out_Delay_without_Diode.jpg
In views C and D, I show the path of electron flow for
an energized contactor and a de-energized contactor. Note
that the diode has no conduction in the energized mode (C)
but provides an alternate path for electron flow in a tight
loop (D) when the circuit is broken.
This does cause the magnetic field to decay more slowly
than if allowed to collapse unrestrained. A few weeks ago
I published a trace that shows how the contactor or relay
is delayed in reacting with a diode installed
http://www.aeroelectric.com/Pictures/Curves/S704-1_Drop-Out_Delay_with_Diode.jpg
. . . as opposed to no diode at all:
http://www.aeroelectric.com/Pictures/Curves/S704-1_Drop-Out_Delay_without_Diode.jpg
Note in the first trace coil voltage is clamped off
at just below ground (.7v diode drop) while in the second
trace we see the voltage go WWWAAAaaaayyyy negative. In
the second trace, had a fire been allowed to form between
the spreading contacts of a switch, the energy dissipated
would have removed metal from the contacts. In the first
trace, arcing is a tiny fraction of what does happen when
the stored energy is not managed.
This whole discussion is about improving life of the controlling
device with one of several techniques . . . with a simple diode
being the simplest and easiest to acquire.
Quote: | I apologize if I am taking up too much of this venue s resouces in trying
to understand this concept. If this is an issue, please let me know and I
will try to gain an understanding by finding someone locally to discuss in
more detail.
|
This is a classroom, not a country club. New students and
teachers come and go with a wide range of knowledge
and skills. This venue's resources are dedicated to
precisely the needs you have expressed.
Bob . . .
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user9253
Joined: 28 Mar 2008 Posts: 1932 Location: Riley TWP Michigan
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Posted: Mon Jun 23, 2008 4:51 pm Post subject: Contactor Diodes |
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Dave,
When battery power is removed from a coil by opening a switch, the coil now becomes a power source and tries to keep the current flowing through itself in same direction that it was flowing before the switch was opened. Current that leaves a source wants to return to that same source (but to the terminal of opposite polarity) by easiest path possible. Although the diode blocked current flow from the battery, the polarity of the current generated by the coil is such that the diode easily conducts it (as long as the voltage is above approximately 1 volt). The majority of the coil-generated current will find it much easier to travel through the short path of the diode to get back to the other end of the coil, rather than through the air between the opening contacts of the switch. The above events only last for a fraction of a second.
It might be easier to understand if one uses a water analogy. Suppose there is a water pump instead of a battery, pipes instead of wires, coiled tubing instead of a contactor coil, valves instead of switches, and a check valve instead of a diode. If the pump were running and valves were suddenly closed on each side of the coil of tubing, the momentum of the water flowing through the coil of tubing would want to keep that water flowing in the same direction. The check valve would give the water an easy path to keep water flowing in the same direction from the outlet of the tubing back to the inlet of the tubing, much easier than trying to go through a closed valve. In a short time, the energy would be spent and the water would stop flowing.
I hope that helps.
Joe Gores
[quote][b]
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bobf(at)feldtman.com Guest
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Posted: Mon Jun 23, 2008 6:21 pm Post subject: Contactor Diodes |
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you must be a teacher! this is excellent
bobf
On 6/23/08, Joe <fran5sew(at)banyanol.com (fran5sew(at)banyanol.com)> wrote:[quote]
Dave,
When battery power is removed from a coil by opening a switch, the coil now becomes a power source and tries to keep the current flowing through itself in same direction that it was flowing before the switch was opened. Current that leaves a source wants to return to that same source (but to the terminal of opposite polarity) by easiest path possible. Although the diode blocked current flow from the battery, the polarity of the current generated by the coil is such that the diode easily conducts it (as long as the voltage is above approximately 1 volt). The majority of the coil-generated current will find it much easier to travel through the short path of the diode to get back to the other end of the coil, rather than through the air between the opening contacts of the switch. The above events only last for a fraction of a second.
It might be easier to understand if one uses a water analogy. Suppose there is a water pump instead of a battery, pipes instead of wires, coiled tubing instead of a contactor coil, valves instead of switches, and a check valve instead of a diode. If the pump were running and valves were suddenly closed on each side of the coil of tubing, the momentum of the water flowing through the coil of tubing would want to keep that water flowing in the same direction. The check valve would give the water an easy path to keep water flowing in the same direction from the outlet of the tubing back to the inlet of the tubing, much easier than trying to go through a closed valve. In a short time, the energy would be spent and the water would stop flowing.
I hope that helps.
Joe Gores
[b]
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Joemotis(at)aol.com Guest
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Posted: Mon Jun 23, 2008 8:29 pm Post subject: Contactor Diodes |
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You win the internet!
Great example.
Thanks
joe
no archivos hombre!!
Gas prices getting you down? Search AOL Autos for fuel-efficient used cars.
[quote][b]
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dvanlanen
Joined: 25 Jul 2006 Posts: 122 Location: Madison, WI
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Posted: Tue Jun 24, 2008 10:17 am Post subject: Contactor Diodes |
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Thanks to Bob and Joe for the great explanations. I now understand clearly. On to the next subject….
Dave
Do Not Archive [quote][b]
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